Program in C and C++ to display day of any given date.

Program in C and C++ to display day of any given date.

C code

#include<stdio.h>
 int c_Code(int c_year)
   {
       if(c_year%4==0&&c_year%100!=0||c_year%400==0)
        return 0;
       else if(c_year==1700||c_year==2100||c_year==2500||c_year==2900)
         return 5;
       else if(c_year==1800||c_year==2200||c_year==2600||c_year==3000)
        return 3;
       else if(c_year==1900||c_year==2300||c_year==2700||c_year==3100)
        return 1;
       else 
     return 0;
 }
  int main()
   {
       char dayPrint[8][15]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};
       int i,cy,cc,yc,yl,day,days=0,month,year,dayCode;
       printf("Enter day, month, year : ");
       scanf("%d%d%d",&day,&month,&year);
       int monthCode[]={31,year%4==0&&year%100!=0||year%400==0?29:28,31,30,31,30,31,31,30,31,30,31};
       yc=(year-1)%100;
       cy=(year-1)-yc;
       yl=yc/4;
       cc=c_Code(cy);
       for(i=0;i<month-1;i++){
          days+=monthCode[i];
       }
       days=days+day;
       dayCode=(cc+yc%7+yl%7+days%7)%7;
       printf("Day : %s",dayPrint[dayCode]);
       return 0;
   }

C++ code

#include<iostream>
 using namespace std;
   int c_Code(int c_year)
   {
       if(c_year%4==0&&c_year%100!=0||c_year%400==0)
        return 0;
       else if(c_year==1700||c_year==2100||c_year==2500||c_year==2900)
         return 5;
       else if(c_year==1800||c_year==2200||c_year==2600||c_year==3000)
        return 3;
       else if(c_year==1900||c_year==2300||c_year==2700||c_year==3100)
        return 1;
       else 
     return 0;
 }
  int main()
   {
       char dayPrint[8][15]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};
       int i,cy,cc,yc,yl,day,days=0,month,year,dayCode;
       cout<<"Enter day, month, year : ";
       cin>>day>>month>>year;
       int monthCode[]={31,year%4==0&&year%100!=0||year%400==0?29:28,31,30,31,30,31,31,30,31,30,31};
       yc=(year-1)%100;
       cy=(year-1)-yc;
       yl=yc/4;
       cc=c_Code(cy);
       for(i=0;i<month-1;i++){
          days+=monthCode[i];
       }
       days=days+day;
       dayCode=(cc+yc%7+yl%7+days%7)%7;
       cout<<"Day : "<<dayPrint[dayCode];
       return 0;
   }

Output :-

 

Related Programs

•   Display month of any given year using c and c++
•   Print calendar for a given year in C and C++