Print following pattern

Print following pattern

1
0	0
1	1	1
0	0	0	0
1	1	1	1	1

#include<stdio.h>
#include<conio.h>
 int main()
  {
    int i,j;
    for(i=1;i<=5;i++)  
      {  
       for(j=1;j<=i;j++) 
    {
      if(i%2==0)
       printf(" 0 ");  
      else
         printf(" 1 ");  
     }
        printf("\n");  
      } 
 return 0;
  }

Output:-